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Update CSS selectors in tutorial

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Eugenio Lacuesta 2020-01-22 10:38:59 -03:00
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15
docs/intro/tutorial.rst
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@ -616,19 +616,24 @@ instance; you still have to yield this Request.
You can also pass a selector to ``response.follow`` instead of a string;
this selector should extract necessary attributes::
href = response.css('li.next a::attr(href)')[0]
yield response.follow(href, callback=self.parse)
for href in response.css('ul.pager a::attr(href)'):
yield response.follow(href, callback=self.parse)
For ``<a>`` elements there is a shortcut: ``response.follow`` uses their href
attribute automatically. So the code can be shortened further::
a = response.css('li.next a')[0]
yield response.follow(a, callback=self.parse)
for a in response.css('ul.pager a'):
yield response.follow(a, callback=self.parse)
To create multiple requests from an iterable, you can use
:meth:`response.follow_all <scrapy.http.TextResponse.follow_all>` instead::
yield from response.follow_all(response.css('a'), callback=self.parse)
anchors = response.css('ul.pager a')
yield from response.follow_all(anchors, callback=self.parse)
or, shortening it further::
yield from response.follow_all(css='ul.pager a', callback=self.parse)
More examples and patterns